b^2-2bc-3c^2=0

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Solution for b^2-2bc-3c^2=0 equation:


Simplifying
b2 + -2bc + -3c2 = 0

Reorder the terms:
-2bc + b2 + -3c2 = 0

Solving
-2bc + b2 + -3c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(b + -3c)(b + c) = 0

Subproblem 1

Set the factor '(b + -3c)' equal to zero and attempt to solve: Simplifying b + -3c = 0 Solving b + -3c = 0 Move all terms containing b to the left, all other terms to the right. Add '3c' to each side of the equation. b + -3c + 3c = 0 + 3c Combine like terms: -3c + 3c = 0 b + 0 = 0 + 3c b = 0 + 3c Remove the zero: b = 3c Simplifying b = 3c

Subproblem 2

Set the factor '(b + c)' equal to zero and attempt to solve: Simplifying b + c = 0 Solving b + c = 0 Move all terms containing b to the left, all other terms to the right. Add '-1c' to each side of the equation. b + c + -1c = 0 + -1c Combine like terms: c + -1c = 0 b + 0 = 0 + -1c b = 0 + -1c Remove the zero: b = -1c Simplifying b = -1c

Solution

b = {3c, -1c}

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